Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
210
1050
21400
25200
Correct answer is A
To form words having 3 consonants and 2 vowels out of 7 consonants and 4 vowels, the number of such words is 7/3C x 4/2C = 35 x 6
= 210
\(\frac{1}{16}\)
\(\frac{1}{6}\)
\(\frac{1}{4}\)
\(\frac{3}{8}\)
Correct answer is C
P( tail on a coin) = \(\frac{1}{2}\)
Even numbers on a care 2, 4 and 6
P( even number on a die) = \(\frac{3}{6}\) = \(\frac{1}{2}\)
P( tail on a coin and even number on a die) = \(\frac{1}{2}\) x \(\frac{1}{2}\) = \(\frac{1}{4}\)
Evaluate ∫\(^2_1\) \(\frac{5}{x}\) dx
1.47
2.67
3.23
3.47
Correct answer is D
∫\(\frac{5}{x}\) dx = 5 ∫\(\frac{1}{x}\) = 5Inx
Since the integral of \(\frac{1}{x}\) is Inx
∫\(^2\) \(_1\)∫ \(\frac{5}{x}\) dx = 5
dx = 5 (In<2 – InIn1)
= 3.4657
= 3.47
Calculate 243\(_{six}\) – 243\(_{five}\) expressing your answer in base 10
0
1
26
46
Correct answer is C
Since they are of different base, convert to base 10
243\(_{six}\) = (2 x 62) + (4 x 61) + (3 x 60)
= 72 + 24 + 3 = 99 base 10
243\(_{six}\) = 2 x 52 + 4 x 51 +3 x 50
50 + 20 + 3 = 73 base 10
Subtracting them, 99 - 73
= 26
4
5
6
7
Correct answer is B
The modal age is the age with the highest frequency, and that is age 5 years with f of 7
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