Which of the following equations is the correct definition of the reactance of an indicator L?
Reactance = (Amplitude of voltage) \(\div\) (Amplitude of current)
Reactance = (Amplitude of voltage) x (Amplitude of current)
Reactance = (Amplitude of current)\(^2\) \(\div\) (Amplitude of voltage)
Reactance = (Amplitude of current)\(^2\) \(\div\) (Amplitude of voltage)\(\frac{1}{2}\)
Correct answer is A
Reactance is the value of an indicator or a capacitor in ohms
I only
II only
I & II only
I, II & III only
Correct answer is C
Rutherford assumed that (I) energy is radiated when electrons are revolving (II) energy is radiated in a continuous mode. These are limitations of Rutherford's model
3.2\(\Omega\)
1.4\(\Omega\)
3.21\(\Omega\)
1.2\(\Omega\)
Correct answer is D
\(\frac{R}{3.6} = \frac{75}{25} = \frac{1}{3}\)
3R = 3.6
R = 1.2\(\Omega\)
all the heat is used to break the bonds holding the molecules of the solid together
the heat capacity has become very large as the substance melts
the heat energy is quickly conducted away
the heat gained is equal to the heat lost by the substance
Correct answer is A
During the transformation of the matter from the solid to the liquid state, the heat supplied does not produce a temperature increase because all the heat is used to break the bonds holding the molecules of the solid together
Lamps in domestic lightings are usually in
series
divergent
convergent
parallel
Correct answer is D
Lamps in lightenings are arranged to reduce the heat losses
- resultant resistance is small for parallel arrangement which indicate low heat losses [Heat \(\alpha\) R]
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