Find the probability that a number selected at random from 21 to 34 is a multiple of 3
311
29
514
513
Correct answer is C
S = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34}
n(S) = 14
multiples of 3 = {21, 24, 27, 30, 33}
n(multiples of 3) = 5
Prob( picking a multiple of 3) = 5/14
−2x−2−73x3+52x2−6x
2x2+73x3−5x+6
12x2+14x−5
−12x−4−14x+5
Correct answer is A
∫(4x−3−7x2+5x−6)dx
= 4x−3+1−3+1−7x2+12+1+5x1+11+1−6x
= −2x−2−73x3+52x2−6x
This table below gives the scores of a group of students in a Further Mathematics Test.
| Score | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Frequency | 4 | 6 | 8 | 4 | 10 | 6 | 2 |
Calculate the mean deviation for the distribution
4.32
2.81
1.51
3.90
Correct answer is C
Score(x) 1 2 3 4 5 6 7 Total Frequency (f) 4 6 8 4 10 6 2 40 fx 4 12 24 16 50 36 14 156 x - ˉx -2.9 -1.9 -0.9 0.1 1.1 2.1 3.1 |x - ˉx| 2.9 1.9 0.9 0.1 1.1 2.1 3.1 f|x - ˉx| 11.6 11.4 7.2 0.4 11 12.6 6.2 60.4
Mean = ∑fx∑f
= 15640
= 3.9
M.D = ∑f|x−ˉx|∑f
= 60.440
= 1.51
This table below gives the scores of a group of students in a Further Mathematics Test.
| Score | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Frequency | 4 | 6 | 8 | 4 | 10 | 6 | 2 |
Find the mode of the distribution.
7
10
5
4
Correct answer is C
Mode = Score with the highest frequency
= 5
36
63
47
81
Correct answer is D
M∝N ; M∝1√P.
∴
M = \frac{k N}{\sqrt{P}}
when M = 3, N = 5 and P = 25;
3 = \frac{5k}{\sqrt{25}}
k = 3
M = \frac{3N}{\sqrt{P}}
when M = 2 and N = 6,
2 = \frac{3(6)}{\sqrt{P}} \implies \sqrt{P} = \frac{18}{2}
\sqrt{P} = 9 \implies P = 9^2
P = 81