JAMB Biology Past Questions & Answers - Page 42

206.

The number of plant species obtained from a population study of a garden is as follows: Guinea grass (15), Ipomoea spp (5), Sida spp (7) and Imperata spp (23)

What is the percentage of occurrence of Imperata spp?

A.

35%

B.

16%

C.

46%

D.

23%

Correct answer is C

No of  Imperata spp = 23

Total plant species = 50


Percentage of imperata spp = \(\frac{23}{50} * 100℅\)

= 46℅

208.

A freshwater plant such as water lily can solve the problem of buoyancy by the possession of

A.

aerenchyma tissues

B.

dissected leaves

C.

thin cell walls of the epidermis

D.

water-repelling epidermis

Correct answer is A

Aerenchyma is found in hydrophytes like water lily.

This tissue encloses air and provides buoyancy to the plant parts.

209.

The appendicular skeleton is composed of the pectoral girdle

A.

pelvic girdle, fore and hind limbs

B.

pelvic girdle and fore limbs

C.

lumbar vertebrae and pelvic girdle

D.

lumbar vertebrae, fore and hind limbs

Correct answer is A

The appendicular skeleton includes the bones of the shoulder girdle, the upper limbs, the pelvic girdle, and the lower limbs.

210.

Which of the following is a measure for the control of bilharzia?

A.

Cutting low bushes around homes

B.

Application of molluscicides in water bodies

C.

Screening windows and doors with mosquito nets

D.

Application of herbicides in water bodies

Correct answer is B

Schistosomiasis, also known as bilharzia or 'snail fever', is a disease caused by parasites (worms called schistosomes) carried by freshwater snails.

Schistosomiasis control focuses on reducing disease through periodic, large-scale population treatment with medication;

a more comprehensive approach including potable water, adequate sanitation, and snail control would also reduce transmission.