Find the value of x if √2x+√2 = 1x−√2
3√2 + 4
3√2 - 4
3 - 2√2
4 + 2√2
Correct answer is A
√2x+2 = x - 1√2
x√2 (x - √2) = x + √2 (cross multiply)
x√2 - 2 = x + √2
= x√2 - x
= 2 + √2
x (√2 - 1) = 2 + √2
= 2+√2√2−1×√2+1√2+1
x = 2√2+2+2+√22−1
= 3√2 + 4
If x is positive real number, find the range of values for which 13x + 12x = 2+3x6x > 14x
x > -16
x > 0
0 < x < 6
0 < x <16
Correct answer is A
13x + 12x = 2+3x6x > 14x
= 4(2 + 3x) > 6x = 12x2 - 2x = 0
= 2x(6x - 1) > 0 = x(6x - 1) > 0
Case 1 (-, -) = x < 0, 6x - 1 > 0
= x < 0, x < 16 (solution)
Case 2 (+, +) = x > 0, 6x - 1 > 0 = x > 0
x > 16
Combining solutions in cases (1) and (2)
= x > 0, x < 16 = 0 < x < 16
Find the simple interest rate percent annum at which N1000 accumulates to N1240 in 3 years.
6%
8%
10%
12%
Correct answer is B
I = PRT100 = 1 = 1240 - 1000 = 240
R = 240×100100×3 = 8%
60√3m
30√3m
20√3m
10√3m
Correct answer is B
h = 30 tan 60
= 30√3