\(\frac{3}{8}\)
\(\frac{1}{3}\)
\(\frac{7}{24}\)
\(\frac{2}{3}\)
Correct answer is B
n(apples) = 9
n(bananas) = 8
n(oranges) = 7
n(\(\varepsilon\)) = 24
Hence Prob(not apple, nor orange) = Prob(banana) = \(\frac{8}{24}\) = \(\frac{1}{3}\)
\(\frac{1}{25}\)
\(\frac{1}{5}\)
\(\frac{4}{25}\)
\(\frac{3}{4}\)
Correct answer is C
\((1 \leq x \leq 25)\) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25}
Number N of x divisible by both 2 and 3 is 4.
n(\(\varepsilon\)) = 25
= \(\frac{N}{n(\varepsilon)}\)
= \(\frac{4}{25}\)
In how many ways can 3 seats be occupied if 5 people are willing to sit?
60
20
5
120
Correct answer is A
5 people can take 3 places in;
5P3 ways, = \(\frac{5!}{(5 - 3)!}\) = \(\frac{5!}{2!}\)
= \(\frac{5 \times 4 \times 3 \times 2!}{2!}\)
= 5 x 4 x 3
= 60 ways
In how many ways can a student select 2 subjects from 5 subjects?
\(\frac{5!}{3!}\)
\(\frac{5!}{2!2!}\)
\(\frac{5!}{2!3!}\)
\(\frac{5!}{2!}\)
Correct answer is C
A student can select 2 subjects from 5 subjects in;
5C3 ways, i.e. = \(\frac{5!}{2!(5 - 2)!}\)
= \(\frac{5!}{2!3!}\)
7
6
3
10
Correct answer is A
Range = Highest score - Lowest score
= 10 - 3
= 7