JAMB Physics Past Questions & Answers - Page 328

1,636.

An ebonite rod rubbed with fur attracts a glass rod rubbed with silk because

A.

ebonite has a negative charge while glass has a positive charge

B.

ebonite has a positive charge while glass has a negative charge

C.

both have negative charges

D.

both have positive charges

Correct answer is A

No explanation has been provided for this answer.

1,637.

The force of repulsion between two point positive charges 5\(\mu\)C and 8\(\mu\)C separated at a distance of 0.02 map art is. [\(\frac{1}{4{\pi}{\varepsilon}_o}\) = 9 x 109Nm2C-2]

A.

1.8 x 10-10N

B.

9.0 x 10-8N

C.

9.0 x 102N

D.

4.5 x 103N

Correct answer is C

F =\(\frac{1}{4{\pi}{\varepsilon}_o}\) x \(\frac {q_1q_2}{r^2}\)

F =\(\frac {5 {\times} 10 {\times} 8 {\times} 10}{0.002 {\times} 0.002}\) x 9 x 10

F = 900N

1,638.

Which of the following are true about the infra-red radiation?

i. it is invisible
ii. it is called heat ray
iii. its frequency is higher than that of blue light
iv. it travels as a transverse wave

A.

i, ii, iii and iv

B.

i, ii, iv only

C.

i, iii, iv only

D.

ii, iii, iv only

Correct answer is B

No explanation has been provided for this answer.

1,639.

A man wears convex lens glasses of focal length 30cm in order to correct his eye defect. instead of the optimum 25cm, his least distance of distinct vision is

A.

14cm

B.

28cm

C.

75cm

D.

150cm

Correct answer is A

F = \(\frac{uv}{u - v}\)

F = +ve

v = -ve

30 = \(\frac {25 {\times} (-v)}{25 - (-v)}\)
v = \(\frac {25 {\times} (-v)}{25+v}\)
v = 14cm

(Note that either negative or positive values go to show the positioning and hence, they are not a strong necessity in your final answer.)

1,640.

The displacement d produced in a glass block of thickness t and refractive index n when an object is viewed through it is

A.

t – n

B.

t (1 + 1/n)

C.

t (1-1/n)

D.

t (1/n - 1)

Correct answer is C

n = \(\frac {\text{real depth}}{\text {apparent depth}{}}\)

n = \(\frac {t}{t-d}\)

\(\frac{t - d}{1}\) = \(\frac{t}{n}\)

-d = \(\frac{t}{n}\) - t

d = - \(\frac{t}{n}\) + t

d = t - \(\frac{t}{n}\)

d =t (1 - \(\frac{1}{n}\))