JAMB Mathematics Past Questions & Answers - Page 327

1,631.

In how many ways can 3 seats be occupied if 5 people are willing to sit?

A.

60

B.

20

C.

5

D.

120

Correct answer is A

5 people can take 3 places in;

5P3 ways, = \(\frac{5!}{(5 - 3)!}\) = \(\frac{5!}{2!}\)

= \(\frac{5 \times 4 \times 3 \times 2!}{2!}\)

= 5 x 4 x 3

= 60 ways

1,632.

In how many ways can a student select 2 subjects from 5 subjects?

A.

\(\frac{5!}{3!}\)

B.

\(\frac{5!}{2!2!}\)

C.

\(\frac{5!}{2!3!}\)

D.

\(\frac{5!}{2!}\)

Correct answer is C

A student can select 2 subjects from 5 subjects in;

5C3 ways, i.e. = \(\frac{5!}{2!(5 - 2)!}\)

= \(\frac{5!}{2!3!}\)

1,634.

If the variance of 3+x, 6, 4, x and 7-x is 4 and the mean is 5, find the standard deviation

A.

\(\sqrt{3}\)

B.

2

C.

3

D.

\(\sqrt{2}\)

Correct answer is B

Let \(\delta^2\) and \(\delta\) denote the variance and standard deviation of the distribution respectively.

But \(\delta^2\) = 4 (given)

Hence \(\delta\) = \(\sqrt{4}\) = 2

1,635.

\(\begin{array}{c|c}Age & 20 & 25 & 30 & 35 & 40 & 45 \\
\hline \text{No. of people} & 3 & 5 & 1 & 1 & 2 & 3 \end{array}\)

Calculate the median age of the frequency distribution in the table above

A.

25

B.

30

C.

35

D.

20

Correct answer is A

N = \(\sum f\) = 15

Hence the median age is the \(\frac{N + 1}{2}\)th age, i.e.

\(\frac{15 + 1}{2}\)th = 8th

From the table, the age that falls on the 8th position when arranged in ascending order is 25years