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JAMB Mathematics Past Questions & Answers - Page 300

1,496.

Divide 2x $^{3}$ + 11x $^2$ + 17x + 6 by 2x + 1.

x² + 5x + 6

2x² + 5x - 6

2x² + 5x + 6

x² - 5x + 6

View answer & explanation

Correct answer is A

No explanation has been provided for this answer.

1,497.

Make $\frac{a}{x}$ the subject of formula $\frac{x + 1}{x - a}$ = m

$\frac{m - 1}{m + 1}$

$\frac{m + 1}{1 - m}$

$\frac{m - 1}{1 + m}$

$\frac{m + 1}{m - 1}$

View answer & explanation

Correct answer is A

$\frac{x + a}{x - a}$ = m

x + a = mx - ma
a + ma = mx - x
a(m + 1) = x(m - 1)

$\frac{a}{x}$ = $\frac{m - 1}{m + 1}$

1,498.

Solve for the equation $\sqrt{x}$ - $\sqrt{(x - 2)}$ - 1 = 0

$\frac{3}{2}$

$\frac{2}{3}$

$\frac{4}{9}$

$\frac{9}{4}$

View answer & explanation

Correct answer is D

$\sqrt{x}$ - $\sqrt{(x - 2)}$ - 1 = 0

= $\sqrt{x}$ - $\sqrt{(x - 2)}$ = 1

= ( $\sqrt{x}$ - $\sqrt{(x - 2)}$ )² = 1

= x - 2 $\sqrt{x(x - 2)}$ + x -2 = 1

= (2x - 3)² = [2 $\sqrt{x(x - 4)}$ ]²

= 4x² - 12x + 9

= 4(x² - 2x)

= 4x² - 12x + 9

= 4x² - 8x

4x = 9

x = $\frac{9}{4}$

1,499.

Factorize r2 - r(2p + q) + 2pq

(r - 2q)(2r - p)

(r - p)(r + p0

(r - q)(r - 2p)

(2r - q)(r + p)

View answer & explanation

Correct answer is C

r2 - r(2p + q) + 2pq = r2 - 2pr -qr + 2pq

= r(r - 2p) - q(r - 2p)

= (r - q)(r - 2p)

1,500.

When the expression pm2 + qm + 1 is divided by (m - 1), it has a remainder is 4, Find p and q respectively

2, -1

-1, 2

3, -2

-2, 3

View answer & explanation

Correct answer is B

pm2 + qm + 1 = (m - 1) Q(x) + 2

p(1)2 + q(1) + 1 = 2

p + q + 1 = 2

p + q = 1.....(i)

pm2 + qm + 1 = (m - 1)Q(x) + 4

p(-1)2 + q(-1) + 1 = 4

p - q + 1 = 4

p - q = 3....(ii)

p + q = 1, p - q = -3

2p = -2, p = -1

-1 + q = 1

q = 2