2.0 x 102K-1
2.0 x 102K-1
5.0 x 10-3K-1
2.0 x 10-5K-1
Correct answer is D
a = \(\frac{1.36}{800 \times (95 - 10)}\)
= 2.0 x 10-5K-1
The thermometric properties of the thermocouple is that is
e.m.f. changes with temperature
resistance changes with temperature
volume changes with temperature
pressure changes with resistance
Correct answer is A
No explanation has been provided for this answer.
1.0N
3.0N
4.0N
5.0N
Correct answer is B
volume of object = \(\frac{400 \times 10^{-2}}{600}\)
= 0.00067m3
volume of paraffin displaced = \(\frac{1}{2}\) x 0.00067
= 0.00034m3
mass of paraffin = 900 x 34 x 10-5
= 0.3kg
weight of paraffin = 0.3 x 10
= 3N = upthrust = tension in the string
9 x 104NM-2
4 x 104NM-2
3 x 104NM-2
2 x 104NM-2
Correct answer is D
P = 2 x 1000 x 10
= 2 x 104NM-2
tan\(\theta\) = \(\frac{1}{10}\)
cot\(\theta\) = \(\frac{1}{10}\)
cos\(\theta\) = \(\frac{1}{10}\)
sin\(\theta\) = \(\frac{1}{10}\)
Correct answer is D
V.R = \(\frac{1}{sin\theta}\)
= 10
sin = \(\frac{1}{10}\)