2x2 - 3x + 5
2x2 - 3x + 3
2x2 - 3x
4
Correct answer is B
∫dy = ∫(4x - 3)dx, y = 2x2 - 3x + C
when y = 5, x = 2, C = 3
y = 2x2 - 3x + 3
For what value of x is the tangent to the curve y = x\(^2\) - 4x + 3 parallel to the x-axis?
3
2
1
6
Correct answer is B
At the point where the tangent is parallel to the x- axis, the slope of the curve = 0.
Given: \(y = x^{2} - 4x + 3\)
\(\frac{\mathrm d y}{\mathrm d x} = 2x - 4\)
\(2x - 4 = 0 \implies 2x = 4 \)
\(x = 2\)
When x = 2, the tangent of the curve is parallel to the x- axis.
tan x cosec x
-cot x cosec x
tan x sec x
-cot x sec x
Correct answer is B
\(\csc x = \frac{1}{\sin x}\)
Using the quotient rule,
\(\frac{\mathrm d y}{\mathrm d x} = \frac{vdu - udv}{v^{2}}\)
= \(\frac{\sin x (0) - 1 (\cos x)}{(\sin x)^{2}}\)
= \(\frac{- \cos x}{\sin^{2} x}\)
= \((\frac{- \cos x}{\sin x}) (\frac{1}{\sin x})\)
= \(- \cot x \csc x\)
60m
30 \(\sqrt{3}\)m
20 \(\sqrt{3}\)m
10 \(\sqrt{3}\)m
Correct answer is B
h = 30 tan 60°
= 30\(\sqrt{3}\)
100o
80 o
50 o
40 o
Correct answer is B
< PYU = < YPQ = 40°(Alternative) = PQ\(\parallel\)UV
< XPQ = < YPQ = 40°, Since QX = QY
therefore < XPY = 80°