The saturated vapour pressure of a liquid increases as the
volume of the liquid increases
volume of the liquid decreases
temperature of the liquid increases
temperature of the liquid decreases
Correct answer is C
No explanation has been provided for this answer.
84s
112s
168s
280s
Correct answer is C
Heat energy = Elect. energy
mc\(\theta\) = power x time
1 x 4200 x (50 - 20) = 750 x t
t = 168s
4200J
2,260,OOOJ
9,040,000J
9,380,000J
Correct answer is C
Heat by water = mc\(\theta\)
Heat by steam = mc\(\theta\) + mL
Difference = mL = 4 x 2,260,000
= 9,040,000J
2.0036m
2.0018cm
2.1800
2.0360m
Correct answer is A
\(\alpha\) = \(\frac{L_2 - L_1}{L_1 \times \Delta \theta}\)
18 x 10-6 = \(\frac{L_2 - 2}{2\times 100}\)
L = 2.0036m
25.0oC
50.0oC
66.7oC
75.0oC
Correct answer is D
100oC ... 90oS
\(\theta\)oC ... 60oS
0oC ... 30oS
\(\frac{\theta - 0}{100 - 0}\) = \(\frac{60 - (-30)}{90 - (-30)}\)
\(\theta\) = 75oC