1:4
2:1
2:3
2:5
Correct answer is C
Given \(\frac{m_{1}}{m_{2}} = \frac{3}{1}\) \(\Rightarrow\) m\(_{1}\) = 3m\(_{2}\)
\(\frac{a_{1}}{a_{2}} = \frac{2}{9}\) = a\(_{1}\) = \(\frac{2a_{2}}{9}\)
\(\frac{F_{1}}{F_{2}}\) = ?
Since F = ma
\(\Rightarrow\) \(\frac{F_{1}}{F_{2}} = \frac{m_{1}a_{1}}{m_{2}a_{2}}\) = \(\frac{(3 \not m_{2})(2 \not a_{2})}{\not m_{2} a_{2} \not a_{3}}\)
\(\frac{F_{1}}{F_{2}} = \frac{2}{3}\) \(\Rightarrow\) 2:3
The inner diameter of a test tube can be measured accurately using a?
micrometer screw gauge
pair of dividers
meter rule
pair of vernier calipers
Correct answer is D
Vernier calipers are also used to measure the internal and external diameters of a tube
beta rays
gamma rays
x-rays
ultra-violet rays
Correct answer is A
Both the electric field and magnetic field affect the β-particles.
24 years
20 years
10 years
2 years
Correct answer is B
Given amount remaining = \(\frac{1}{64}\)
= \(\frac{1}{64} = \frac{1}{(2)^{6}}\)
\(\therefore\) = \(\frac{120 \text {years}}{6}\) = 20 years
\(\Rightarrow\) T\(\frac{1}{2}\) = 20 years
6630.0V
663.0V
66.3V
6.6V
Correct answer is C
Given f = 1.6 x10\(^{16}\)H\(_{3}\), h = 6.63 x 10\(^{-39}\)Js
e = 1.6 x 10\(^{-19}\)C, V = ?
V = \(\frac{w}{e} = \frac{hf}{e}\) = \(\frac{1.6 \times 10^{16} \times 6.63 \times 10^{34}}{1.6 \times 10^{-19}}\)
= 66.3V