JAMB Mathematics Past Questions & Answers - Page 274

1,366.

Evaluate (x + \(\frac{1}{x}\) + 1)2 - (x + \(\frac{1}{x}\) + 1)2

A.

4x2

B.

(\(\frac{2}{x}\) + 2)2

C.

4

D.

4(1 + x)

Correct answer is D

(x + \(\frac{1}{x}\) + 1)2 - (x + \(\frac{1}{x}\) + 1)2

= (x + \(\frac{1}{x}\) + 1 + x + \(\frac{-1}{x}\) - 1)(x - \(\frac{1}{x}\) + 1 - x + \(\frac{1}{x}\) + 1)

= (2x) (2 + \(\frac{2}{x}\)) = 2x x 2(1 + \(\frac{1}{x}\))

4x (1 + \(\frac{1}{x}\)) = 4x + 4

= 4(1 + x)

1,367.

Which of the following is a factor of 15 + 7x - 2x2

A.

x + 3

B.

x - 3

C.

x - 5

D.

x + 5

Correct answer is C

Factorize 15 + 7x - 2x2

(5 - x)(3 + 2x); suppose 15 + 7x = 2x2 = 0

∴ (5 - x)(3 + 2x) = 0

x = 5 or x = -\(\frac{3}{2}\)

Since 5 is a root, then (x - 5) is a factor

1,368.

Make x the subject of the relation \(\frac{1 + ax}{1 - ax}\) = \(\frac{p}{q}\)

A.

\(\frac{p + q}{a(p - q)}\)

B.

\(\frac{p - q}{a(p + q)}\)

C.

\(\frac{p - q}{apq}\)

D.

\(\frac{pq}{a(p - q)}\)

Correct answer is B

\(\frac{1 + ax}{1 - ax}\) = \(\frac{p}{q}\) by cross multiplication,

q(1 + ax) = p(1 - ax)

q + qax = p - pax

qax + pax = p - q

∴ x = \(\frac{p - q}{a(p + q)}\)

1,369.

If \(\sqrt{x^2 + 9}\) = x + 1, solve for x

A.

5

B.

4

C.

3

D.

2

E.

1

Correct answer is B

\(\sqrt{x^2 + 9}\) = x + 1

x2 + 9 = (x + 1)2 + 1

0 = x2 + 2x + 1 - x2 - 9

= 2x - 8 = 0

2(x - 4) = 0

x = 4

1,370.

If N225.00 yields N27.00 in x years simple interest at the rate of 4% per annum, find x

A.

3

B.

4

C.

12

D.

17

Correct answer is A

Principal = N255.00, Interest = 27.00

year = x Rate: 4%

∴ 1 = \(\frac{PRT}{100}\)

27 = \(\frac{225 \times 4 \times T}{100}\)

2700 = 900T

T = 3 years