JAMB Chemistry Past Questions & Answers - Page 265

1,321.

If the rate law obtained for a given reaction is rate = k(X)ⁿ (Y)^m, what is the overall order of the reaction?

n/m

n + m

n - m

View answer & explanation

Correct answer is C

No explanation has been provided for this answer.

1,322.

2SO2(g) + O2(g) → 2SO3. In the reaction above, the standard heats of formation of SO2(g) and SO3(g) are -297 KJ mol-1 and -396 kJ/mol respectively. The heat change of the reaction is?

-99 kJ mol^-

-198 kJ mol^-

+198 kJ mol^-

+683kJ mol^-

View answer & explanation

Correct answer is B

2SO2 + O2 → 2SO3
2(-297) 2(-396)
-594 -792
Heat change = heat of product - heat of reactants = -792 - (-594) = -198kj mol-

1,323.

2H₂S_(g) + SO_2(g) + H₂O_(I) → 3S_(s) + 3H₂O_(I)..........(i) 3CuO_(s) + 2NH_3(g) → 3Cu_(s) + 3H₂O_(I) + N_2(g).........(II) In the equations above, the oxidizing agent (I) and the reducing agent in (II) respectively are?

H₂S_{and NH₃}

SO₂ and CuO

SO₂ and NH₃

H₂S_{and CuO}

View answer & explanation

Correct answer is C

No explanation has been provided for this answer.

1,324.

What is the oxidation number of Z in K₃ZCl₆?

-3

-6

View answer & explanation

Correct answer is B

No explanation has been provided for this answer.

1,325.

How many Faraday of electricity are required to deposit 0.20 mole of nickel, if 0.10 Faraday of electricity deposited 2.98g of nickel during electrolysis of its aqueous solution?

(Ni = 58.7, 1F = 96 500 C mol^-)

0.20

0.30

0.40

0.50

View answer & explanation

Correct answer is C

No of mole → (2.98)/(58.7) ..............0.1

2.0 .................x
∴ x = (0.2)/(2.98) x 58.7 x 0.40

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