0.89 mol
1.90 mol
3.80 mol
5.70 mol
Correct answer is A
\(V_1\) = \(10dm^3\), \(V_2\) = ?, \(P_1\) = 4atm = 4 x 760 = 3040mmHg, \(P_2\) = 760mmHg \(T_1\) = 273ºc = 273 + 273 = 546K, \(T_2\) = 273K
Using the general gas law = \(\frac{P_1 V_1}{ T_1} = \frac{P_2 V_2}{T_2}\)
\(V_2 = \frac{P_1 V_1 T_2}{P_2 T_1}\)
\(V_2 = \frac{ 3040 \times10 \times273}{760 \times546}\)
\(V_2 = 20dm^{-3}\)
1mole of a gas = \(22. 4dm^{3}\)
x = \(20.0dm^{3}\)
= 0.89mol.
A mixture of iron and sulphur can be separated by dissolving the mixture in?
steam
dilute hydrochloric acid
dilute sodium hydroxide
benzene
Correct answer is D
No explanation has been provided for this answer.
The addition of water to calcium oxide leads to?
a physical change
a chemical change
the formation of a mixture
an endothermic change
Correct answer is B
No explanation has been provided for this answer.
88.71 KJ
85.48 KJ
-204.00 KJ
-3427.40 KJ
Correct answer is D
∆G = ∆H - T∆S; T = 2s° + 273 = 298 k
∆G = 89 - 298 x 11.8 = -3427.4
HCOOH
C2H5COOH
CH3COOH
C3H7COOH
Correct answer is C
Conc. of KOH = 39 x 0.02 = 0.78 g/dm3
25cm3 require 0.03 g of CnH2n + 1 COOH 1000CM3 → x x = (1000) / (25) x 0.03 = 1.2g
CnH2n + 1COOH + KOH → CnH2n + 1 COOK + H2O
from (MAVA) / (MB x VB) = (1) / (1) (MA x 1.2) / (0.02 x 0.78) = (1) / (1)
MA = 0.013
Con. = Molarity x Molecular Mass
Molecular Mass = (0.78) / (0.013) x 60
CnH2n + 1 COOH = 60
12n + 1 (2n + 1) + 12 + 32 + 1 = 6
14n = 60 - 46; n = (14) / (14) = 1
∴ CH3COOH