Simplify \(\sqrt{160r^2 + \sqrt{71r^4 + \sqrt{100r^8}}}\)
9r2
12\(\sqrt{3r}\)
13r
\(\sqrt{13r}\)
Correct answer is C
\(\sqrt{160r^2 + \sqrt{71r^4 + \sqrt{100r^8}}}\)
Simplifying from the innermost radical and progressing outwards we have the given expression
\(\sqrt{160r^2 + \sqrt{71r^4 + \sqrt{100r^8}}}\) = \(\sqrt{160r^2 + \sqrt{71r^4 + 10r^4}}\)
= \(\sqrt{160r^2 + \sqrt{81r^4}}\)
\(\sqrt{160r^2 + 9r^2}\) = \(\sqrt{169r^2}\)
= 13r
N60 000.00
N54 000.00
N48 000.00
N42 000.00
Correct answer is B
use "T" to represent the total profit. The first receives \(\frac{1}{3}\) T
remaining, 1 - \(\frac{1}{3}\)
= \(\frac{2}{3}\)T
The seconds receives the remaining, which is \(\frac{2}{3}\) also
\(\frac{2}{3}\) x \(\frac{2}{3}\) = \(\frac{4}{9}\)
The third receives the left over, which is \(\frac{2}{3}\)T - \(\frac{4}{9}\)T = (\(\frac{6 - 4}{9}\))T
= \(\frac{2}{9}\)T
The third receives \(\frac{2}{9}\)T which is equivalent to N12000
If \(\frac{2}{9}\)T = N12, 000
T = \(\frac{12 000}{\frac{2}{9}}\)
Total share[T] = N54, 000
The first receives \(\frac{1}{3}\) of T → \(\frac{1}{3}\) * N54, 000 = N18,000
The second receives \(\frac{4}{9}\) of T → \(\frac{4}{9}\) * N54, 000 = N24,000
The third receives \(\frac{2}{9}\)T which is equivalent to N12000.
Adding the three shares give total profit of N54,000
Simplify and express in standard form \(\frac{0.00275 \times 0.0064}{0.025 \times 0.08}\)
8.8 x 10-1
8.8 x 10-2
8.8 x 10-3
8.8 x 103
Correct answer is C
\(\frac{0.00275 \times 0.0064}{0.025 \times 0.08}\)
Removing the decimals = \(\frac{275 \times 64}{2500 \times 800}\)
= \(\frac{88}{10^4}\)
\(88 x 10^{-4} = 88 x 10^{1} x 10^{-4} = 8.8 x 10^{-3}\)
\(\frac{3}{16}\)
\(\frac{7}{16}\)
\(\frac{9}{16}\)
\(\frac{13}{16}\)
Correct answer is A
You can use any whole numbers (eg. 1. 2. 3) to represent all the mangoes in the basket.
If the first child takes \(\frac{1}{4}\) it will remain 1 - \(\frac{1}{4}\) = \(\frac{3}{4}\)
Next, the second child takes \(\frac{3}{4}\) of the remainder
which is \(\frac{3}{4}\) i.e. find \(\frac{3}{4}\) of \(\frac{3}{4}\)
= \(\frac{3}{4}\) x \(\frac{3}{4}\)
= \(\frac{9}{16}\)
the fraction remaining now = \(\frac{3}{4}\) - \(\frac{9}{16}\)
= \(\frac{12 - 9}{16}\)
= \(\frac{3}{16}\)
At what rate would a sum of N100.00 deposited for 5 years raise an interest of N7.50?
\(\frac{1}{2}\)%
2\(\frac{1}{2}\)%
1.5%
25%
Correct answer is C
Interest I = \(\frac{PRT}{100}\)
∴ R = \(\frac{100 \times 1}{100 \times 5}\)
= \(\frac{100 \times 7.50}{500 \times 5}\)
= \(\frac{750}{500}\)
= \(\frac{3}{2}\)
= 1.5%