\(\frac{2}{3}\)
\(\frac{2}{15}\)
\(\frac{1}{2}\)
\(\frac{1}{4}\)
Correct answer is C
\(\begin{array}{c|c} 1 & 2 & 3 & 4\\\hline 1(1, 1) & (1, 2) & (1, 3) & (1, 4)\\ \hline 2(2, 1) & (2 , 2) & (2, 3) & (2, 4) \\ \hline 3(3, 1) & (3, 2) & (3, 3) & (3, 4)\\ \hline 4(4, 1) & (4, 2) & (4, 3) & (4, 4)\end{array}\)
sample space = 16
sum of nos. removed are (2), 3, (4), 5
3, (4), 5, (6)
(4), 5, (6), 7
(5), 6, 7, (8)
Even nos. = 8 of them
Pr(even sum) = \(\frac{8}{16}\)
= \(\frac{1}{2}\)
1
2
3
4
Correct answer is B
\(\begin{array}{c|c} Scores & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \text{No. of students} & 1 & 4 & 5 & 6 & x & 2\end{array}\)
Average = 3.5
3.5 = \(\frac{(1 \times 1) + (2 \times 4) + (3 \times 5) + (4 \times 6) + 5x + (6 \times 2)}{1 + 4 + 5 + 6 + x + 2}\)
\(\frac{3.5}{1}\) = \(\frac{1 + 8 + 15 + 24 + 5x + 12}{18 + x}\)
\(\frac{3.5}{1}\) = \(\frac{60 + 5x}{18 + x}\)
60 + 5x = 3.5(18 \(\div\) x)
60 + 5x = = 63 + 1.5x
5x - 1.5x = 63 - 60
1.5x = 3
x = \(\frac{3}{1.5}\)
\(\frac{30}{15}\) = 2
3
16
18
32
Correct answer is D
Mean of 10 numbers = 16
The total sum of numbers = 16 x 10 = 160
Mean of 11 numbers = 18
Total sum of numbers = 11 x 18
= 198
The 11th no. = 198 - 160
= 38
3
16
18
32
Correct answer is D
Mean of 10 numbers = 16
The total sum of numbers = 16 x 10 = 160
Mean of 11 numbers = 18
Total sum of numbers = 11 x 18
= 198
The 11th no. = 198 - 160
= 38
48o
84o
92o
276o
Correct answer is D
Given that 4, 16, 30, 20, 10, 14 and 26
Adding up = 120
nos \(\geq\) 16 are 16 + 30 + 20 + 26 = 92
The requires sum of angles = \(\frac{92}{120}\) x \(\frac{360^o}{1}\)
= 276o