If \(12_{e} = X_{7}\), where e = 12, find X.
20
15
14
12
Correct answer is A
\(12_{12} = 1 \times 12^{1} + 2 \times 12^{0} = 12 + 2 = 14_{10}\)
| 7 | 14 |
| 7 | 2 rm 0 |
| 0 rm 2 |
\(\therefore 12_{e} = 20_{7}\)
2, 9, 5
2, 9, 7
2, 3, 5, 7
2, 3, 7, 9
Correct answer is C
\(2520 = 2 \times 2 \times 2 \times 3 \times 3 \times 5 \times 7\) in terms of its prime factors. Hence, the prime factors of 2520 are 2, 3, 5, 7.
Evaluate 2700 000 x 0.03 ÷ 18 000
4.5 x 100
4.5 x 101
4.5 x 102
4.5 x 103
Correct answer is A
\(2700000 \times 0.03 \div 18000\)
= \(\frac{2700000 \times 0.03}{18000}\)
= \(\frac{81000}{18000} = 4.5 \times 10^{0}\)
Which of the following is in descending order?
\(\frac{9}{10} \frac{4}{5} \frac{3}{4} \frac{17}{20}\)
\(\frac{4}{5} \frac{9}{10} \frac{3}{4} \frac{17}{20}\)
\(\frac{9}{10} \frac{17}{20} \frac{4}{5} \frac{3}{4}\)
\(\frac{4}{5} \frac{9}{10} \frac{17}{20} \frac{3}{4}\)
Correct answer is C
\(\frac{9}{10} \frac{4}{5} \frac{3}{4} \frac{17}{20}\) = \(\frac{18, 16, 15, 17}{20}\)
\(\frac{4}{5} \frac{9}{10} \frac{3}{4} \frac{17}{20}\) = \(\frac{16, 18, 15, 17}{20}\)
\(\frac{9}{10} \frac{17}{20} \frac{4}{5} \frac{3}{4}\) = \(\frac{18, 17, 16, 15}{20}\)
∴ \(\frac{9}{10}; \frac{17}{20}; \frac{4}{5}; \frac{3}{4}\) is in descending order.
Find the probability that a number selected at random from 41 to 56 is a multiply of 9
\(\frac{1}{8}\)
\(\frac{2}{15}\)
\(\frac{3}{16}\)
\(\frac{7}{8}\)
Correct answer is A
Given from 41 to 56
41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56
The nos multiple of 9 are: 45, 54
P(multiple of 9) = \(\frac{2}{16}\)
= \(\frac{1}{8}\)