JAMB Physics Past Questions & Answers - Page 240

1,196.

A block of mass 2.04kg resting on a smooth horizontal plane is acted upon simultaneously by two-forces, 10N due North and 10N due East. The magnitude of the acceleration produced by the force on the block is

A.

0.10ms-2

B.

7.07ms-2

C.

10.00ms-2

D.

14.10ms-2

E.

20.00ms-2

Correct answer is B

R = \(\sqrt {10^2 + 10^2}\)

R = 14.14N

R = F = ma

14.14 = 2 x a

a = 7.07ms-1

1,197.

If a car starts from rest and moves with a uniform acceleration of 10ms-2 for ten seconds, the distance it covers in the last one second of its motion is

A.

95m

B.

100m

C.

500m

D.

905m

E.

1000m

Correct answer is A

Distance in 105, using, x = ut + \(\frac{1}{2}\)at2

x = (0 x 10) + (\(\frac{1}{2}\) x 10 x 10 x 10) = 500m

distance in 9s; x - (0 x 9) + (\(\frac{1}{2}\) x 10 x 9 x 9) = 405m

distance in last is = difference

= 500 - 405

= 95m

1,199.

Which of the following statements are true about the spring balance and the chemical balance?

i. both are used to measure the mass of an object.
ii. either of them may be used to measure the weight of an object.
iii. the spring balance works on the principle of Hooke's law while the chemical balance works on the principle of moments.
iv. a change in gravity does the readings of a spring balance but not that of a chemical balance.

A.

i, and iv

B.

ii and iii

C.

ii and iv

D.

i, ii and iii

E.

i and iii

Correct answer is B

-  the spring balance works on the principle of Hooke's law while the chemical balance works on the principle of moments.

- The mass of a body is measured using beam or chemical

- Chemical balance is a delicate instrument which is used to weigh small amounts of substances

- The weight of a body can be measured using a spring balance

1,200.

A simple pendulum with a period of 2.0s has its length doubled. Its new period is

A.

1.00s

B.

1.41s

C.

0.3s

D.

2.83s

E.

4.00s

Correct answer is D

Using \(\frac{T_1}{T_2}\) = \(\sqrt\frac{L_1}{L_2}\)

\(\frac{2}{T_2}\) = \(\sqrt\frac{L_1}{2L_1}\)

T2 = 2.83sec