JAMB Physics Past Questions & Answers - Page 24

116.

An astronomical telescope is said to be in normal adjustment when the?

A.

eye is accommodated

B.

focal length of an object lens is longer than that of eye piece

C.

final image is at the near point of eye

D.

final image is at infinity

Correct answer is D

A normal arrangement is an arrangement where the principal focus of objective coincides with the eyepiece so that the final image is at infinity

117.

The velocities of light in air and glass are 3.0 x 10\(^8\)ms\(^{-1}\) and 2.0 x 10\(^8\)ms\(^{-1}\) respectively. If the angle of refraction is 30º, the sine of the angle of incidence is? 

A.

0.33

B.

0.50

C.

0.67

D.

0.75

Correct answer is D

\(\frac{\text {sin i}}{\text {sin r}}\) = \(\frac{\text {velocity in air}}{\text {velocity in glass}}\)

\(\frac{\text {sin i}}{\text {sin 30}}\) = \(\frac{3 \times 10^{8}}{2 \times 10^{8}}\)

Sin i = \(\frac{3}{4}\) = 0.75

118.

The inside portion of part of a hollow metal sphere of diameter 20cm is polished. The portion will therefore form a?

A.

concave mirror of focal length 5cm

B.

concave mirror of focal length 10cm

C.

convex mirror of focal length 5cm

D.

convex mirror of focal length 10cm

Correct answer is C

Concave Mirror: It is a spherical mirror whose outer surface is polished and inner or concave side is reflecting surface.

Convex Mirror: It is a spherical mirror whose inner surface is polished and outer side or convex side is the reflecting surface.

f = \(\frac{m}{4}\) = f = \(\frac{d}{4}\)

f = \(\frac{20}{4}\) = 5cm

119.

A man stands 4m in front of a plane mirror. If the mirror is moved 1m towards the man, the distance between him and his new image is?

A.

3m

B.

5m

C.

6m

D.

10m

Correct answer is C

Objects distance (u) = image distance (v)

object distance = 3m

|uv| = 3 + 3 = 6m

120.

The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 180Hz?

A.

4

B.

3

C.

2

D.

1

Correct answer is B

f\(_{0}\) = 40H\(_{3}\)

1st overtone = 2f\(_{0}\) = 80H\(_{3}\)

2nd overtone = 3f\(_{0}\) = 120H\(_{3}\)

3rd overtone = 4f\(_{0}\) = 160H\(_{3}\)

4th overtone = 5f\(_{0}\) = 200H\(_{3}\)

\(\therefore\) Number of overtones between 40H\(_{3}\) and 180H\(_{3}\) = 3