A good calorimeter should be of
low specific heat capacity and low heat conductivity
low specific heat capacity and high heat conductivity
high specific heat capacity and low heat conductivity
high specific heat capacity and low heat conductivity
dull surface and low heat conductivity
Correct answer is B
No explanation has been provided for this answer.
\(\frac{1}{4}\)
\(\frac{1}{2}\)
4
1
2
Correct answer is D
Heat = mc\(\theta\)
Hx = Dx x Vx x Cx x \(\theta\)x
Hy = Dy x Vy x Cy x \(\theta\)y
\(\frac{H_x}{H_y}\) = \(\frac{D_x \times V_x \times C_x \times \theta_x}{D_x \times V_x \times C_x \times \theta_x}\)
= 2 x \(\frac{1}{2}\)
= 1
Water shows anomalous behaviour.
below 0oC
between 0oC and 4oC
at exactly 4oC
between 4oC and 100oC
above 100oC
Correct answer is B
No explanation has been provided for this answer.
force
force/m
work
force/m3
energy/m3
Correct answer is C
slope = pressure \(\div\) \(\frac{1}{volume}\)
= \(\frac{N}{m^3}\) x \(\frac{m^3}{1}\)
= Nm = work
573oC
327oC
300oC
110oC
27oC
Correct answer is E
General Gas Law:
\(\frac{P_1 V_1}{T_1}\) = \(\frac{P_2 V_2}{T_2}\)
where T\(_1\) = -73 + 273 = 200k, T\(_2\) = ?,
V\(_1\) = 1, V\(_2\) = \(\frac{1}{2V}\),
P\(_1\) = 1.5, P\(_2\) = 4.5
T\(_2\) = \(\frac{P_2 V_2 T_1}{P_1 V_1}\)
T\(_2\) = \(\frac{4.5 * 1/2 * 200}{1.5 X 1}\)
T\(_2\) → 300k or 27ºC