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JAMB Physics Past Questions & Answers - Page 233

1,161.

A uniform cylindrical block of wood floats in water with one-third of its height above the water level, in a liquid of relative density 0.8, what fraction of its height will be above the liquid level?

$\frac{1}{6}$

$\frac{1}{5}$

$\frac{1}{3}$

$\frac{4}{5}$

$\frac{5}{6}$

View answer & explanation

Correct answer is E

Height inside H₂O = $\frac{2}{3}$

R.d = $\frac{\text{height inside}H_2O}{\text{height inside liquid}}$

0.8 = $\frac{\frac{2}{3}}{X}$

1,162.

A metal cube of volume 10³mm³ is lowered into a measuring cylinder containing water. If the internal cross-sectional area of the cylinder is 1.5 x 10²mm², by how much does the water level rise in the cylinder?

6.67 x 10⁰mm

8.50 x 10²mm

1.15 x 10³mm

2.50 x 10³mm

1.50 x 10⁵mm

View answer & explanation

Correct answer is A

Height = $\frac{volume}{area}$

= Height = $\frac{10^3}{1.5 \times 10^2}$

= 6.67mm

1,163.

The areas of the effort and load pistons of a hydraulic press are 0.5m² and 5m² respectively. If a force F₁ of 100N is applied on the effort piston, the force F₂ on the load is

10N

100N

500N

1000N

5000N

View answer & explanation

Correct answer is D

$\frac{load}{area}$ = $\frac{effort}{area}$

$\frac{load}{5}$ = $\frac{100}{0.5}$

load = 1000N

1,164.

A force of 100N stretches an elastic string to a total length of 20cm. If an additional force of 100N stretches the string 5cm further, Find the natural length of the string

15cm

12cm

10cm

8cm

5cm

View answer & explanation

Correct answer is A

Using, f₁ = f₂

e₁ = 20 - L ; e_{2 = 5cm

$\frac{f_1}{e_1}$ = $\frac{f_2}{e_2}$

$\frac{100}{20 - L}$ = $\frac{100}{5}$

hence, L = 15cm}

1,165.

A 0.05kg bullet travelling at 500ms^-1 horizontally strikes a thick vertical wall. It stops after penetrating through the wall horizontal distance of 0.25m. What is the magnitude of the average force the wall exerts on the bullet?

25N

50N

250N

500N

25 000N

View answer & explanation

Correct answer is E

F = ma

= m $\frac{(v^2 - u^2)}{2s}$

F = 0.05 $\frac{(0 - (500)^2)}{2 \times 0.25}$

F = 25 000N

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