The perpendicular bisector of UV
A circle with UV as radius
A line parallel to the line UV
A circle with the line UV as the diameter
Correct answer is D
No explanation has been provided for this answer.
Find the total surface area of solid cone of radius 2\(\sqrt{3}\)cm and slanting side 4\(\sqrt{3}\)
8\(\sqrt{3}\pi \)cm2
24\(\pi \)cm2
15\(\sqrt{3}\pi \)cm2
36\(\pi \)cm2
Correct answer is D
Total surface area of a solid cone
r = 2\(\sqrt{3}\)
= \(\pi r^2\) + \(\pi\)rH
H = 4\(\sqrt{3}\), \(\pi\)r(r + H)
∴ Area = \(\pi\)2\(\sqrt{3}\) [2\(\sqrt{3}\) + 4\(\sqrt{3}\)]
= \(\pi\)2\(\sqrt{3}\)(6\(\sqrt{3}\))
= 12\(\pi\) x 3
= 36\(\pi \)cm2
An arc of a circle of radius 6cm is 8cm long. Find the area of the sector
5\(\frac{1}{3}\)cm2
24cm2
36cm2
84cm2
Correct answer is B
Radius of the circle r = 6cm, Length of the arc = 8cm
Area of sector = \(\frac{\theta}{360}\) x \(\pi\)r2........(i)
Length of arc = \(\frac{\theta}{360}\) x 2\(\pi\)r........(ii)
from eqn. (ii) \(\theta\) = \(\frac{240}{\pi}\), subt. for \(\theta\) in eqn (i)
Area x \(\frac{240}{1}\) x \(\frac{1}{360}\) x \(\frac{\pi 6}{1}\)
= 24cm\(^2\)
69m
57m
51m
21m
Correct answer is C
QY = 452 + 242 = 2025 + 576
= 2601
QY = \(\sqrt{2601}\)
= 51
A regular polygon of n sides has 160o as the size of each interior angle. Find n
18
16
14
12
Correct answer is A
No explanation has been provided for this answer.