In the diagram above, XY = 8cm and OX = 5cm. Find Oz
9cm
3.4cm
9.1cm
3cm
Correct answer is D
hyp = 5cm, adj = \(\frac{8cm}{2}\) 4cm, opp = xcm
Pythagoras theorem:
hyp\(^2\) = opp\(^2\) + adj\(^2\)
5\(^2\) = x\(^2\) + 4\(^2\)
x\(^2\) = 25 - 16
x = √9
x = 3cm
10m/s
2m/s
5m/s
6m/s
Correct answer is C
No explanation has been provided for this answer.
Evaluate \(^{n^2 + 1}\)C\(_{n+5}\) if n = 3
55
45
35
25
Correct answer is B
\(^{3^2 + 1}\)C\(_{3+5}\)
\(^{9 + 1}\)C\(_{3+5}\)
\(^{10}\)C\(_{8}\) = \(\frac{10!}{8! 2!}\)
\(\frac{10 * 9 * 8!}{8! 2!}\) = \(\frac{10 * 9}{2}\)
= 45
The coordinates of the mid-point of the line joining the points (-3,5) and (2,10) is given by?
( \(\frac{1}{2}\), \(\frac{15}{2}\) )
( \(\frac{1}{2}\), \(\frac{-15}{2}\) )
( \(\frac{-1}{2}\), \(\frac{-15}{2}\) )
( \(\frac{-1}{2}\), \(\frac{15}{2}\) )
Correct answer is D
Given Data: x\(_1\) = -3, x\(_2\) = 2, y\(_1\) = 5, y\(_2\) = 10
coordinates of the mid-point of the line = (\(\frac{x_1 + x_2}{2}\) , \(\frac{y_1 + y_2}{2}\))
(\(\frac{-3 +2}{2}\) , \(\frac{5 + 10}{2}\))
= \(\frac{-1}{2}\)) , \(\frac{15}{2}\))
3000
1000
2000
4000
Correct answer is C
if 20 students = 10000
: #500 per student
#1,000,000 ÷ 500
= 2,000 cover students
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