0.85 PN-m-2
0.86 PN-m-2
1.16 PN-m-2
1.18 PN-m-2
2.85 PN-m-2
Correct answer is C
At constant volume,
\(\frac{P_1}{T_1}\) = \(\frac{P_2}{T_2}\)
\(\frac{P}{27 +273}\) = \(\frac{P_2}{77 + 273}\)
\(300P_2 = 350P\)
P2 = 1.16 PNm\(^{-2}\)
80 cal
10 cal
8 cal
800 cal
400 cal
Correct answer is D
Quantity of heat = ml
= 10 x 80
= 800 cal
A temperature 20°C is the same as
36oF
68oF
11.1oF
43.1oF
25oF
Correct answer is B
212°F ... 100°C
\(\theta\)°F ... 20°C
32°F ... 0°C
\(\frac{\theta - 32}{212 - 32}\) = \(\frac{20 - 0}{100 - 0}\)
180 = 5(\(\theta\) - 32)
5\(\theta\) = 180 + 160 = 340
\(\theta\) = 68°F
convection
osmosis
capillarity
diffusion
conductivity
Correct answer is D
No explanation has been provided for this answer.
ii, iv, and v
ii, iii and vi
i, iii and vi
i, iii and v
i, iv and v
Correct answer is A
No explanation has been provided for this answer.