3.0s
4.5s
6.0s
7.5s
9.0s
Correct answer is A
s = ut + \(\frac{1}{2}gt^2\)
45 = 0 + 5t2
t = 3s
5
4
3
2
1
Correct answer is C
No explanation has been provided for this answer.
0.25ms-2
3.00ms-2
4.00ms-2
9.00ms-2
16.00ms-2
Correct answer is B
slope = acceleration
a = \(\frac{v_2 - v_1}{t_2 - t_1} = \frac{60- 15}{20 - 5}\)
= 3ms-2
20m
40m
80m
160m
200m
Correct answer is C
Initial horizontal velocity = 20ms-1
Initial vertical velocity = 0
s = ut + \(\frac{1}{2}gt^2\) = 0 x 5 x 42
= 80m
A body moves with a constant speed but has an acceleration. This is possible if it
moves in a straight line
moves in a circle
is oscillating
is in equilibrum
has a varrying acceleration
Correct answer is B
No explanation has been provided for this answer.
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