24
18
12
9
8
Correct answer is B
12 men in 9 days,
1 day in \(12 \times 9\) men
In 6 days we have \(\frac{12 \times 9}{6}\) men
= \(\frac{108}{6}\)
= 18 men
Find the value of log\(_{10}\)\(\frac{1}{40}\), given that log10\(_4\) = 0.6021
1.3979
2.3979
-1.6021
2.6021
Correct answer is C
log\(_{10}\)\(\frac{1}{40}\) = log\(_{10}\)1 - (log\(_{10}\)4 + log\(_{10}\)10)
= 0 - 1.6021
= -1.6021
Find the value of (4\(^{\frac{1}{2}}\))\(^6\)
1
2
4
6
64
Correct answer is E
The powers will multiply when the bracket is expanded
The multiplied powers: \(\frac{1}{2}\) * 6 → 3
: 4\(^3\) = 4 * 4* 4
→ 64
If x3 - 12x - 16 = 0 has x = -2 as a solution then the equaion has
x = -4 as a solution also
3 roots all different
3 roots with two equal and the third different
3 roots all equal
only one root
Correct answer is B
No explanation has been provided for this answer.
Solve the simultaneous linear equations: 2x + 5y = 11, 7x + 4y = 2
x = -8, y = 1
x = -2, y = 4
x = \(\frac{-34}{27}\), y = \(\frac{73}{27}\)
x = 7, y = -9
Correct answer is C
2x + 5y = 11.......(i)
7x + 4y = 2.......(ii)
(i) x 7 \(\to\) 14x + 35y = 77.........(iii)
(ii) x 2 \(\to\) 14x + 8y = 4........(iv)
(iii) - (iv)
27y = 73
y = \(\frac{73}{27}\)