The wave motion above has a frequency
0.1Hz
0.2Hz
5Hz
10Hz
100Hz
Correct answer is C
No explanation has been provided for this answer.
The effect of closing the key K in the circuit shown above would be to
increase the current by 0.6A
reduce the current by 0.6A
increase the current by 0.4A
keep the current unchanged
Correct answer is C
When K is open, the total resistance
R = 8\(\Omega\) + 2\(\Omega\) = 10\(\Omega\)
I = \(\frac{V}{R}\) = \(\frac{6}{10}\)
= 0.6A
When K is closed, we have
\(\frac{1}{R}\) = \(\frac{1}{8}\) + \(\frac{1}{8}\)
⇒ \(\frac{1}{R}\) = \(\frac{1}{4}\)
⇒ R = 4\(\Omega\)
The total resistance R = 4\(\Omega\) + 2\(\Omega\)
= 6\(\Omega\)
I = \(\frac{6}{6}\)
= 1A
Hence, I = 1A - 0.6A = 0.4A increase
\( 15^{\circ} \)
\( 30^{\circ} \)
\( 45^{\circ} \)
\( 60^{\circ} \)
\( 75^{\circ} \)
Correct answer is B
No explanation has been provided for this answer.
\( \alpha = \beta \)
the efractive index of glass is \( \frac{sin\theta}{sin\alpha} \)
The ray suffers total internal reflection if \( \beta \) is greater than the critical angle
the efractive index of glass is \( \frac{sin\alpha}{sin\beta} \)
Correct answer is D
No explanation has been provided for this answer.
Zero
0.2N.m
0.4N.m
0.8N.m
0.6N.m
Correct answer is A
No explanation has been provided for this answer.
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