650
900
800
250
Correct answer is A
We first find the lorry's initial velocity
a = \(4ms^-2\), s= 250m, t= 10, u=?
⇒ ut + \(\frac{1}{2}×4×(10^2)
⇒250= 10u + 200
⇒ 250-200 = 10u
⇒ 50 = 10u
⇒U =\frac{50}{10}\) = \(5ms^-1\)
For the next 10s, we set t=20s
= s = (5 × 20) + \(\frac{1}{2}×4×{20^2}\)
= s = 100 + 800
⇒ 900 m
;Distance covered:900-250 =650m
18.0V
12.0V
16.0V
20.0V
Correct answer is D
ε = 24.0 V, r=1Ω, R=5.0Ω
terminal p·d = ?
ε = IR+Ir = I(R+r)
⇒ IR+Ir = I(R+r)
⇒ I = \(\frac{24}{5+1}\)
⇒ I =\(\frac{24}{6}\)
⇒ I = 4 A
terminal p·d = 4 × 5
terminal p·d = 20.0 V
422.7
220.14
464.53
321.74
Correct answer is A
h=32·8m, p= \(1×10^3kgm^-3\)
g=9·8 \(ms^-2\) , \(P_a\)=101·3KPa
\(P_T\)= ?
P=hpg
⇒\(32·8×1×10^3 × 9·8\)=321440 \(P_a\)
⇒321·44KPa
⇒ \(P_T\) =321.44+101.3
;\(P_T\)=422·7KPa
70
62
80
42
Correct answer is A
Relative Humidity= \(\frac {partial pressure of H2O}{saturated vapor pressure of H2O}\)×100%
S.v.p. of water at 40°c = 55.3
⇒ Relative Humidity= \(\frac{38.8}{55.3}\)×100%
Relative Humidity= 70%
195 m
271 m
391 m
136 m
Correct answer is C
U= 75 \(ms^-1\) =22º, g= 10 \(ms^-2\) , R=?
R= \(\frac{U^2sin2\theta}{g}\)
⇒R= \(\frac{75^2×sin2(22)}{10}\)
⇒R= \(\frac{5625×Sin44}{10}\)
⇒R= \(\frac{5625×0.6947}{10}\)
⇒R= \(\frac{3907.69}{10}\)
⇒ 391m
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