both M and N have acquired negative charges
both M and N have acquired positive charges
M has acquired negative charge and N positive charge
N has acquired negative charge and M positive charge
Correct answer is D
No explanation has been provided for this answer.
V/8
V/4
V/3
V/2
Correct answer is C
Using the voltage- divider method which states that the output voltage is directly proportional to the input voltage and the ratio of R1 and R2, given by:
\(V_{a}\) = \(\frac{R_{a}}{R_{T}}\times V_{T}\)
\(R_{T}\) = \(1 + \frac{4\times4}{4+4}\)
⇒ \(R_{T}\) = \(3\Omega\)
\(V_{1}\) = \(\frac{1}{3}V\)
Q1/Q2
E/Q1
E/(Q1-Q2)
E/(Q1-Q2)
Correct answer is B
\(efficiency = \frac{workout}{workinput}\)
= \(\frac{E}{Q_1}\)
1.25m
0.50m
0.25m
0.05m
Correct answer is B
P.E\(_{mgh}\) = \(\frac{1}{2}\) * k * x\(^2\)
mgh = \(\frac{1}{2}\) * k * x\(^2\)
50 * 10 * 10 = \(\frac{1}{2}\) * 4 * 10\(^4\) * x\(^2\)
→ x\(^2\) = \(\frac{5000 * 2}{4 * 10^4}\)
→ x = √[0.25]
: x = 0.50m
(m1-m2)g
m1g
m2g
(m1+m2)g
Correct answer is B
No explanation has been provided for this answer.
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