In the figure, TSP = 100° and PRQ = 20°. Find PQR.
140o
120o
75o
30o
Correct answer is A
PSR = 80°
\(\therefore\) SRP = 20°
\(\implies\) RPQ = 20°
x = 140°
The sketch is the curve of y = ax2 + bx + c. Find a, b and c respectively
1, 0, -4
-2, 2, -4
0, 1, -4
2, -2, -4
2, -2, -4
Correct answer is A
Given the graph and the curve y = ax2 + bx + c the roots are x - 2 and 2 while its equation (x + 2)(x - 2) = y
y = x2 - 4 i.e. y = x2 + 0x - 4
a = 1, b = 0 and c = -4
\(\frac{a \pi^2}{3} (x + 3y) \)
a\(\pi ^2\)y
\(\frac{a \pi ^2}{3}\)(y + x)
(\(\frac{1}{3} a \pi ^2 x + y\))
Correct answer is A
No explanation has been provided for this answer.
In the figure, PQRS is a square of sides 8cm. What is the area of \(\bigtriangleup\)UVW?
64 sq. cm
40 sq.cm
50 sq.cm
10 sq.cm
Correct answer is D
No explanation has been provided for this answer.
In this figure, PQ = PR = PS and SRT = 68<sup>o</sup>. Find QPS
136o
124o
12o
68o
Correct answer is A
Since PQRS is quadrilateral 2y + 2x = QPS = 360o
i.e. 2(y + x) + QPS = 360o
QPS = 360o - 2(y + x)
But x + y + 68o = 180o
x + y = 180o - 68o = 180o
x + y = 180o - 68o
= 112o
QPS = 360o - 2(112o)
360o - 224o = 136o
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