The value of T in the figure above is
10.0N
11.8N
20.0N
40.0N
Correct answer is D
No explanation has been provided for this answer.
P = Q + R
P = Q - R
P = R - Q
P + Q + R = O
Correct answer is A
Addition of vectors:
P = Q + R
25s
1/50s
1/100s
1/200s
Correct answer is C
No explanation has been provided for this answer.
0.8A
1.0A
1.6A
2.4A
Correct answer is D
\(E = I(R + r)\)
\(I = \frac{E}{R + r}\)
\(\frac{1}{R} = \frac{1}{12} + \frac{1}{6} = \frac{1}{4}\)
\(R = 4\Omega\)
\(I = \frac{12}{1 + 4} = \frac{12}{5}\)
= 2.4A
In the fig above, XY is of length 1m, The value of R at balance point Z is
3.0Ω
13.3Ω
15.0Ω
30.0Ω
Correct answer is D
At null deflection, p.d across R = p.d across xz
p.d across 20Ω = p.d across zy
\(\frac{R}{20}\) = \(\frac{60}{40}\)
R = 30Ω
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