5N in the direction of east
5N in the direction of west
5V3N in the direction of west
10N in the southwest direction
Correct answer is B
The horizontal (eastward) component of the 10N force is = 10 cos60
→ 10 x 0.5 = 5N.
The equilibrant force needed to stop the body moving eastward must act in exactly the
opposite direction.
Therefore, the needed force is 5N in the direction of West
\( \theta _3 \)
\( \theta _2 \)
\( \theta _1 \)
\( \theta _4 \)
Correct answer is A
\( \theta _3 \) shows the angle of deviation
When the sun, moon and the earth are as shown in the diagram above an observer standing in X is in
Penumbra and sees a partial eclipse
Penumbra and sees a total eclipse
umbra and sees a partial eclipse
umbra and sees a total eclipse
Correct answer is A
No explanation has been provided for this answer.
destructively to produce a wave of larger amplitude
destructively to produce a wave of smaller amplitude
constructively to produce a wave of larger amplitude
constructively to produce a wave of smaller amplitude
Correct answer is A
No explanation has been provided for this answer.
tan θ = coefficient of static friction
cos θ = coefficient of dynamic friction
sin θ = coefficient of sliding friction
sec θ = limiting frictional force
Correct answer is A
No explanation has been provided for this answer.
JAMB Subjects
Aptitude Tests