0.2
0.5
2
5
8
Correct answer is B
No explanation has been provided for this answer.
54°C
108°C
150°C
327°C
600°C
Correct answer is D
V1T1=V2T2
Given V2=2V1
T_{1} = 27°C + 273 = 300k
\frac{V_{1}}{300} = \frac{2V_{1}}{T_{2}}
\frac{1}{300} = \frac{2}{T_{2}} \implies T_{2} = 600k or 327°C
When electrical power is transmitted over long distances, the voltage is stepped up so that
the resistance of the wire may be increased proportionately to the potential difference
the time of transmissions between the generating and the receiving stations may be reduced
there is increased current to produce brighter lights.
the rate of electrical consumption is increased.
the energy waste may be minimised as the current is lowered.
Correct answer is E
No explanation has been provided for this answer.
Which of the following is used in a nuclear reactor to slow down fast moving neutrons?
graphite rods
carbon dioxide gas
liquid sodium metal
concrete shield
boron rods
Correct answer is A
No explanation has been provided for this answer.
The half-life of a radioactive substance is 2 seconds. Calculate the decay constant.
2.890 s-1
1.445 s-1
0.576 s-1
0.347s-1
0.152 s-1
Correct answer is D
T_{\frac{1}{2}} = \frac{\ln 2}{\lambda}
where T_{\frac{1}{2}} = half-life of element; \lambda = decay constant.
= \frac{0.693}{\lambda}
\therefore 2 = \frac{0.693}{\lambda}
\lambda = \frac{0.693}{2}
= 0.3465 s^{-1}
\approxeq 0.347 s^{-1}