In the diagram |XY| = 12cm, |XZ| = 9cm, |ZN| = 3cm and ZY||NM, calculate |MY|
3cm
4cm
5cm
6cm
Correct answer is B
\(\frac{|YM|}{|YX|} = \frac{|ZM|}{|ZX|}\)
\(\frac{|YM|}{12} = \frac{3}{9}\)
|YM| = 3 x \(\frac{12}{9}\)
|MY| = 4cm
N676.50
N820
N1,640
N4,920
Correct answer is C
I = N123; R = 3%' T = 2\(\frac{1}{2}\) yrs; P = \(\frac{100 \times 1}{RT}\)
P = \(\frac{100 \times 123}{3 \times 2.5}\)
principal(P) = N1640
10%
20%
50%
60%
Correct answer is C
Number that score less than 5: 5 + 6 + 4 + 3 + 2 = 20
Total number of students: 5 + 6 + 4 + 3 + 2 + 4 + 6 + 5 + 1 + 3 + 1 = 40.
%age of students that failed: \(\frac{20}{40} \times 100% = 50%\)
12
9
8
7
Correct answer is D
Excellent = 360° - (120° + 90° + 80°)
= 70°
Number of excellent students = \(\frac{70}{360} \times 36\)
= 7 students
Find the area of the trapezium above.
91 cm2
78 cm2
60 cm2
19 cm2
Correct answer is C
Area of trapezium = \(\frac{1}{2} (a + b) \times h\)
= \(\frac{1}{2} (7 + 13) \times 6\)
= \(60 cm^{2}\)
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