JAMB Mathematics Past Questions & Answers - Page 102

506.

Evaluate log717

A.

1.35

B.

1.353

C.

1.455

D.

0.455

Correct answer is C

log717

= [log 17 ÷ log7]

= [1.2304 ÷ 0.8451]

[100.0899 ÷ 101.9270]

= 1.455(antilog)

507.

If an investor invest N450,000 in a certain organization in order to yield X as a return of N25,000. Find the return on an investment of N700,000 by Y in the same organization.

A.

N14,950.50K

B.

N25,150.30K

C.

N15,000.00K

D.

N38,888.90K

Correct answer is D

[Return ÷ Investment] as a ratio ;

i.e The Ratio is Return : Investmen

[(Return1÷ Investment1 ) = (Return2÷ Investment2)]

R1 = N 25000

R2 =?

I1 = N450,000,

I1 = N 700000

(25000 ÷ 450000) = (R2 ÷ 700000)

R2 = [(25000 × 700000 ) ÷ 450000]

= N38,888.90K

∴ The return on a investment of Y = N38888.90K

508.

Given that S and T are sets of real numbers such that S = {x : 0 \(\leq\) x \(\leq\) 5} and T = {x : − 2 < x < 3} Find S \(\cup\) T

A.

−3 < x < \(\leq\)3

B.

−2< x < \(\leq\)5

C.

2< x < \(\geq\) −5

D.

−1< x \(\geq\) \(\leq\)2

Correct answer is B

S = {0, 1, 2, 3, 4, 5}

T = {− 1, 0, 1, 2}

S \(\cup\) T = {− 1, 0, 1, 2, 3, 4, 5 }

⇒ − 2 < x ≤ 5

509.

Determine the third term of a geometrical progression whose first and second term are 2 and 54 respectively

A.

1458

B.

1485

C.

1345

D.

1258

Correct answer is A

1st G.P. = a =2

2nd G.P. = ar\(^{2 −1}\) = 54

2(r) = 54

r = 54/2 = 27

r = 27

3rd term = ar\(^2\) = (2) (27)\(^2\)

2 × 27 × 27

= 1458

510.

Find the distance between the points (-2,-3) and (-2,4)

A.

3m

B.

2.4m

C.

3.2m

D.

7.0m

Correct answer is D

No explanation has been provided for this answer.