JAMB Chemistry Past Questions & Answers

506.

A fixed mass of gas occupies 92cm3 at 3°C. What will be its volume at 18C if the pressure remains constant?

15.3cm³

87.3cm³

2.0cm³

97.0cm³

Correct answer is D

$\frac{V_{1}}{T_{1}}$ = $\frac{V_{2}}{T_{2}}$
$T_{1}$ = 3 + 273 = 276K
$T_{2}$ = 18 + 273 = 291K
$V_{1}$ = $92cm^{3}$
$V_{2}$ = ?
$V_{2}$ = $\frac{V_{1}T_{2}}{T_{1}}$

= $\frac{92 \times 291}{276}$
= $97.0cm^{3}$

507.

A liquid that will dissolve fat is

hydrochloric acid

calcium hydrochloride

kerosene

water

View answer & explanation

Correct answer is C

Kerosene is only liquid that will dissolve fat. Option A,B,D will not dissolve fat because of their chemical composition

508.

Which of the following metals burns with brick red

View answer & explanation

Correct answer is B

Calcium is the only metal that burn with brick red flame. Option A,C,D will not burn with brick red flame rather burn with brick blue flame

509.

The above orbital diagram shown the electronic configuration of

chlorine

nitrogen

calcium

neon

View answer & explanation

Correct answer is B

Nitrogen has an electronic configuration of 7 i.e
1s2 2ps2 2p3. option A,C,D are chlorine 17, calcium 20, neon 10

510.

If the volume of a given mass of gas at 298 K and pressure of 205.2 x 10 $^3$ Nm $^{-2}$ is 2.12dm $^3$ , what is volume of the gas at s.t.p? (Standard pressure = 101.3 x 10 $^3$ Nm $^{-2}$ , Standard temperature = 273K)

39.3dm ³

22.4dm³

4.93dm³

3.93dm³

0.393dm³

View answer & explanation

Correct answer is D

V $_1$ = 2.12dm $^3$ , V $_2$ = ?

P $_1$ = 205.2 x 10 $^3$ Nm $^{-2}$ , P $_2$ = 101.3 x 10 $^3$ Nm $^{-2}$

T $_1$ = 293K, T $_2$ = 273K

Using $\frac{P_1 * V_1}{T_1}$ = $\frac{P_2 * V_2}{T_2}$

: V $_2$ = $\frac{P_1 * V_1 * T_2}{P_2 * T_1}$

→ $\frac{205.2 x 10^3 * 2.12 * 273}{101.3 x 10^3 * 293}$

= 4.0dm $^3$

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