How much of magnesium is required to react with 260cm3 of 0.5 M HCl? [Mg = 24]
0.3g
1.5g
2.4g
3.0g
Correct answer is B
No explanation has been provided for this answer.
The number of atoms of chlorine present in 5.85g of NaCl is [Avogaro's Number = 6.02 x 1023]
6.02 x 1022
5.85 x 1023
6.02 x 1023
5.85 x 1024
Correct answer is A
The number of atoms of chloride present in 5.85g of NaCl is 5.85 x 6.0 x 1023
= 6.02 x 1022
HF + N2F2 \(\to\) N2HF3
2HF + N2F2 \(\to\) 2NHF2
2HF + N2F2 \(\to\) N2H2F3
HF + 2N2F2 \(\to\) N4HF2
Correct answer is B
No explanation has been provided for this answer.
The Avogadro number of 24g of magnesium is the same as that of
1g of hydrogen molecules
16g of oxygen molecules
32g of oxygen molecules
35.5g of chlorine molecules
Correct answer is C
24mg = 1 mole of magnesium and
32g of O2 = mole of O2
i, iii and iv
iii only
ii, iii and i
iv only
Correct answer is D
i, ii will have no effect because the number of mole of reactants(volume) is equal to the number of mole of the product(volume) and iii will also have no effect since the forward reaction which favours the production of hydrogen is exothermic, therefore, the production of hydrogen will be favored by iv only.