Two groups of male students cast their votes on a particular proposal. The result are as follows:
| In favor | Against | |
| Group A | 128 | 32 |
| Group B | 96 | 48 |
If a student in favor of the proposal is selected for a post, what is the probability that he is from group A?
8/19
16/35
10/19
4/7
4/5
Correct answer is A
Probability that a student in favor is group A
= \(\frac{128}{128 + 32 + 96 + 48}\)
= \(\frac{128}{304}\)
= \(\frac{8}{19}\)