A man is standing in the corridor of a 10-storey building and looking down at a tall tree in front of the building. He sees the top of the tree at angle of depression of 30o. If the tree is 200m tall and the man's eyes are 300m above the ground, calculate the angle of depression of the foot tree as seen by the man

30^o

60^o

45^o

25^o

Correct answer is B

Let x rep. the angle of depression of the foot of the tree.

tan 30^o = \(\frac{y}{100}\)

y = 100 tan 30^o

= 57.8

By Pythagoras, AC² = 300² + 58²

= 900 + 3354

tan x = \(\frac{opp}{adj}\)

= \(\frac{58}{300}\)

= 0.19

tan x = 0.19

x = tan 0.19

= 60^o

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