The first term a of an A.P is equal to twice the common difference d. Find, in terms of d, the 5th term of the A.P.
4d
5d
6d
a + 5d
2a + 4d
Correct answer is C
Tn = a + (n - 1)d; AP; a = 2d; Tn = 2d + (n - 1)d T5 = 2d + (5 - 1)d = 2d + 4d = 6d
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