What is the probability of having an odd number in a single toss of a fair die?
1/6
1/3
1/2
2/3
5/6
Correct answer is C
n(S) = 6(odd) = {1, 3, 5} n(odd) = 3 pr(odd) = \(\frac{n(odd)}{n(S)}\) 3/6 =1/2
Personality Test
Data Interpretation Questions and Answers
Puzzles Questions and Answers
Typing Speed and Accuracy Test
Quantitative Reasoning Questions and Answers
Nigeria General Knowledge Questions and Answers
Logical Reasoning Questions and Answers
Verbal Reasoning Questions and Answers
Numerical Reasoning Questions and Answers
Microsoft Office Questions and Answers
Abstract Reasoning Questions and Answers
Situational Judgement Questions and Answers
Spatial Reasoning Questions and Answers
See all →