What is the probability of having an odd number in a sing...
What is the probability of having an odd number in a single toss of a fair die?
1/6
1/3
1/2
2/3
5/6
Correct answer is C
n(S) = 6(odd) = {1, 3, 5}
n(odd) = 3
pr(odd) = \(\frac{n(odd)}{n(S)}\) 3/6 =1/2
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\(\begin{vmatrix} -2 & 1 & 1 \\ 2 & 1 & k \\1 & 3 & -1 \end{vmatrix}\) = 23...
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