Find the value of x for which the function f(x) = 2x3 - x...
Find the value of x for which the function f(x) = 2x3 - x2 - 4x + 4 has a maximum value
2/3
1
- 2/3
-1
Correct answer is B
f(x) = 2x3 - x2 - 4x – 4
f’(x) = 6x2 - 2x – 4
As f’(x) = 0
Implies 6x2 - 2x – 4 = 0
3x – x – 2 = 0 (By dividing by 2)
(3x – 2)(x + 1) = 0
3x – 2 = 0 implies x = -2/3
Or x + 1 = 0 implies x = -1
f’(x) = 6x2 - 2x – 4
f’’(x) = 12x – 2
At max point f’’(x) < 0
∴f’’(x) = 12x – 2 at x = -1
= 12(-1) – 2
= -12 – 2 = -14
∴Max at x = 1
Calculate the perimeter, in cm, of a sector of a circle of radius 8cm and angle 45o...
Each of the base angles of a isosceles triangle is 58° and the verticles of the triangle li...
Evaluate log5(\( y^2x^5 ÷ 125b½) \)...
Simplify log10 a\(\frac{1}{3}\) + \(\frac{1}{4}\)log10 a - \(\frac{1}{12}\)log10a7...