$PQRS is a trapezium in which |PS| = 9cm, |QR| = 15cm, |PQ| = $2\sqrt{3}, \angle PQR = 90^o and \angle QRS = 30^o$. Calculate the area of the trapezium$

PQRS is a trapezium in which |PS| = 9cm, |QR| = 15cm, |PQ| = $2\sqrt{3}, \angle PQR = 90^o and \angle QRS = 30^o$. Calculate the area of the trapezium

$24\sqrt{3} cm^2$

$36\sqrt{3} cm^2$

$42\sqrt{3} cm^2$

$72\sqrt{3} cm^2$

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Correct answer is A

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PQRS is a trapezium in which |PS| = 9cm, |QR| = 15cm, |PQ| = \(2\sqrt{3}, \angle PQR = 90^o and \angle QRS = 30^o\). Calculate the area of the trapezium

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