45o
63o
75o
90o
Correct answer is B
Area of a sector = \(\frac{\theta}{360}\times \pi r^2\\55=\frac{\theta}{360}\times \frac{22}{7}\times \frac{10\times 10}{1}\\\theta=\frac{360 \times 55 \times 7}{22 \times 10 \times 10}\\\theta = 63^{\circ}\)
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