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If sinx=45, find \(\frac{1 + \cot^2 x}{\csc...

If sinx=45, find 1+cot2xcsc2x1.

A.

132

B.

259

C.

313

D.

411

Correct answer is B

sinx=oppHyp=45

52 = 42 + adj2

adj2 = 25 - 16 = 9

adj = 9 = 3

tanx=43

cotx=143=34

cot2x=(34)2=916

cscx=1sinx

= 145=54

csc2x=(54)2=2516

= \frac{25}{16} \div \frac{9}{16}

= \frac{25}{9}