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Three forces \(F_{1} = (8 N, 300°), F_{2} = (6 N, 090&de...

Three forces F_{1} = (8 N, 300°), F_{2} = (6 N, 090°) and F_{3} = (4 N, 180°) act on a particle. Find the vertical component of the resultant force.

A.

2 N

B.

10 N

C.

(4 + 4\sqrt{3})N

D.

(6 - 4\sqrt{3})N

Correct answer is D

The vertical component = 8 \sin 300 + 6 \sin 90 + 4 \sin 180

= -4\sqrt{3} + 6 + 0

= (6 - 4\sqrt{3}) N