2√x(2x+√2)
4(2x+√x)(2+12√x)
4(2x+√x)(2+√x)
8(2x+√x)(2+√x)
Correct answer is B
y=2(2x+√x)2
Let u=2x+√x
y=2u2
dydu=4u
dudx=2+12√x
∴
= 4u(2 + \frac{1}{2\sqrt{x}})
= 4(2x + \sqrt{x})(2 + \frac{1}{2\sqrt{x}})
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