-30
-18
-6
6
Correct answer is A
∫(3x2−2x−12)dx=3x2+12+1−2x1+12−12x
= x3−x2−12x
(x3−x2−12x)|3−2=((33)−(32)−12(3))−((−23)−(−22)−12(−2))
= (27−9−36)−(−8−4+24)=−18−12=−30
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